LeetCode: 罗马数字转化为整数

问题

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999.

翻译

给出一个罗马数字，将其转化为整数。 输入被限定在在1到3999之间。

解决方法

func romanToInt(s string) int {
    var result int
    for len(s) > 0 {
        if len(s) >= 2 {
            curr := findRoman(s[:2])
            if curr != 0 {
                result += curr
                s = s[2:]
                continue
            }

        }
        result += findRoman(s[:1])
        s = s[1:]
    }
    return result
}

func findRoman(s string) int {
    switch s {
    case "I":
        return 1
    case "IV":
        return 4
    case "V":
        return 5
    case "IX":
        return 9
    case "X":
        return 10
    case "XL":
        return 40
    case "L":
        return 50
    case "XC":
        return 90
    case "C":
        return 100
    case "CD":
        return 400
    case "D":
        return 500
    case "CM":
        return 900
    case "M":
        return 1000
    default:
        return 0
    }
}